1.

Considering H_(2)O as a weak field ligand, the number of unpaired electrons in [Mn(H_(2)O)_(6)]^(2+) will be (At. no of Mn = 25) :

Answer»

FIVE
two
four
three.

Solution :`Mn (II):3d^(5)`. In the presence of weak field ligands, there will be no PAIRING of electrons. THEREFORE, it will form high spin complex and will have five unpaired electrons.


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