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Considering the circuit and data given in the diagram calculate the currents flowing in the diodes D_(1) and D_(2) with linear characteristics.Forward resistance of D_(1) and D_(2) is 20 Omega |
Answer» Solution :Since the positive of bettery is connected to P-type both DIODES `D_(1)` and `D_(2)` are forward biased .Hence they may be replaced by short (closed ) switch associated with their forward RESISTANCE as shown in Fig.  The resistance of `20Omega` and `20Omega` in parallel `(1)/(R)=(1)/(20)+(1)/(20)=(2)/(20)` (or) `R=(20)/(2)=10 Omega` Therefore ,total CURRENT 1 in the circuit `I=(1)/(100+10)=(1)/(110)` amp and `I_(1)=I_(2)=(1)/(2)xx(1)/(110)=(1)/(220)amp` |
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