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Considering the circuit and data given in the diagram, calculate the currents flowing in the diodes D_(1) and D_(2). Forward resis- tance of D_(1) and D_(2) is 20Omega |
Answer» Solution :Since the positive terminal of battery is connected to P-type of both DIODES `D_(1) and D_(2)` they are FORWARD biased. These diodes are replaced by with their forward RESISTANCES as shown in FIG. The resistance of `20Omega` in PARALLEL `(1)/(R)=(1)/(20)+(1)/(20)=(2)/(20)` Therefore, total current I in the circuit `I=(1)/(100+10)=(1)/(110)" amp and "` `I_(1)=I_(2)=(1)/(2)xx(1)/(110)=(1)/(220)" amp"` |
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