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Considering the parameters such as bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy, compare the oxidising power of F_2 and Cl_2 |
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Answer» Solution :Bond dissociation enthalpy : `Cl_2 gtF_2` Electron gain enthalpy : `CL gt F` HYDRATION enthalpy : `F^(.) gt Cl^(-)` Though bond dissociation enthalpy and electron gain enthalpy of chlorine is higher than fluorine, fluorine is stronger oxidizing agent than chlorine because of its very HIGH hydration enthalpy which results in large positive value of ELECTRODE potential of fluorine. Thus `F_2` is stronger oxidizing agent than `Cl_2`. |
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