1.

Considering the reaction:

Answer»

`( +, -, -)`
`(-, + , +)`
`(-,-,-)`
`(-, + , -)`

Solution :`C_(s) + O_(2)(g) rightarrow CO_(2)(g) + 393.5` Kj
`DELTAH = -Delta S= + , Delta G = -`
Its an EXOTHERMIC reaction.Therefore `DeltaH = -ve` as energy is released during an exothermic reaction.As its a spontaneous reaction, `Delta G = -ve`.Also entropy or randomness increases while moving from LHS to RHS.Therefore `DELTAS = + ve`.


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