1.

Considerthe figure and answer the questions (i) to (vi) given below : (i) Redraw the diagram to show the direction of electron flow. (ii) Is silver plate the anode or cathode ? (iii) What will happen if salt bridge is removed ? (iv) When will the cell stop functioning ? (v) How will concentration of Zn^(2+) ions and Ag^(+) ions be affected when the cell functions ? How will the concentration of Zn^(2+) ions and Ag^(+) ions be affected after the cell becomes 'dead' ?

Answer»

Solution :(i) The flow of eectrons takes place from zinc plate towards COPPERPLATE in the outer circuit.
(ii) Silver plate acts as cathode.
(iii) Cell will stop working because the inner circuit does not exist any more.
(iv) When `E_(cell)`=0
(v) Concentration of `Zn^(2+)`(AQ) ions will gradually decrease while that of `Ag^(+)`(`mu`aq) ions will increase.
(vi) When the cell becomes dead (`E_(cell)`=0), the concentration of `Zn^(2+)` (aq) and `Ag^(+)` (aq) ions will not change any more.


Discussion

No Comment Found