1.

Considerthereaction2NO_((g) ) +O_(2(g) )to2NO_(2(g)).if(d [NO_(2)])/(dt)=0.052 M//sthen-(d[O_(2)])/(dt) will be

Answer»

`0.052 M//s`
`0.114M//s`
`0.026M//s`
`-0.026 M//s`

SOLUTION :`"RATE"=-(1)/(2)(d[NO])/(DT)=-(d[O_(2)])/(dt)=+(1)/(2) (d[NO_(2)])/(dt)`
`-(d[O_(2)])/(dt)=(1)/(2)xx0.052 =0.026 m//s`


Discussion

No Comment Found

Related InterviewSolutions