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Construct a 3 × 2 matrix whose elements are given by aij = (2i – j). |
Answer» Given: aij = (2i – j) Now, a11 = (2 × 1 – 1) = 2 – 1 = 1 a12 = 2 × 1 – 2 = 2 – 2 = 0 a21 = 2 × 2 – 1 = 4 – 1 = 3 a22 = 2 × 2 – 2 = 4 – 2 = 2 a31 = 2 × 3 – 1 = 6 – 1 = 5 a32 = 2 × 3 – 2 = 6 – 2 = 4 Therefore, A = \(\begin{bmatrix}1 &0 \\[0.3em]3& 2 \\[0.3em]5 & 4\end{bmatrix}\) |
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