Construct a ΔABC given that AB= 45cm, BC = 6 cm and
Answer»
Steps of Construction: i) Draw a LINE segment BC = 4.5 cm ii) With B as centre and radius 6 cm and C as centre and radius 5 cm, draw arcs which intersect each other at A. iii) Join AB and AC. ABC is the required triangle. iv) Draw the angle bisector of ∠BAC v) Draw lines parallel to AB and AC at a distance of 2 cm, which intersect each other and AD at O. vi) With centre O and radius 2 cm, draw a circle which touches AB and AC.