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Construct a quadrilateral PQRS in which sides PO = 3 cm, QR = 4 cm, RS = 3.5 cm, SP = 4 cm and diagonal PR = 5 cm. Measure angle POR using a protractor.​

Answer»

MATHSConstruct a trapezium PQRS in which PQ is PARALLEL to SR , PQ = 8 cm ∠ PQR = 70 o , QR = 6 cm and PS = 6 cm. CALCULATE its area.ShareStudy laterANSWERGiven:PQ is parallel to SR , PQ = 8 cm, ∠ PQR = 70 o QR = 6 cm and PS = 6 cm.Steps for constructionStep 1 : Draw a rough diagram and mark the given measurements.Step 2 : Draw a line segment PQ = 8 cm.Step 3 : At Q on PQ make ∠ PQX whose measure is 70 o .Step 4 : With Q as CENTRE and 6 cm as radius draw an arc. This cuts $$\overline{QX}$$ at R.Step 5 : Draw RY parallel to OP .Step 6 : With Q as centre and radius 6 cm draw an arc cutting RY at S.Step 7 : Join PS . PQRS is the required trapezium.Step 8 : From S draw ST ⊥ PQ and measure the length of ST. ST = h = 5.6 cm, RS = b = 6 cm, PQ = a = 8 cm.Calculation of area:In the trapezium PQRS, a = 8 cm, b = 3.9 cm and h = 5.6 cm.Area of the trapezium ABCD = 21 h(a+b)= 21 (5.6)(8+3.9)= 21 × 5.6×11.9 =33.32 cm 2 solution



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