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Construct a rombus in which measures of the diagnols are 8cm and 6cm.plzz tell me fasttt plzzzzzzzz |
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Answer» Answer: LET Rhombus be PQRS where PR and QS are its diagonals Steps of construction: Steps of construction:(i) Draw a LINE segment PR=8cm Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O. Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each(IV) Join PQ,QR,RS and SP Steps of construction:(i) Draw a line segment PR=8cm(ii) Draw its perpendicular bisector XY intersecting it at O.(iii) From XY, cut off OQ=OS=6/2=3cm each(iv) Join PQ,QR,RS and SPThus, PQRS is the required rhombus |
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