Construct ∆ ABC, in which BC =5.2 cm, ∠ACB = 45° and perimeter – InterviewSolution

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1.	Construct ∆ ABC, in which BC =5.2 cm, ∠ACB = 45° and perimeter of ∆ ABC is 10 cm.
Answer» Construct $∆$ ABC, in which BC =5.2 cm, $∠$ ACB = $45^{°}$ and perimeter of $∆$ ABC is 10 cm.

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