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construct an isosceles triangle in which the length of each of it's side is 5cm and the angle between them is 105 . |
Answer» <html><body><p>To construct: An isosceles <a href="https://interviewquestions.tuteehub.com/tag/triangle-1427233" style="font-weight:bold;" target="_blank" title="Click to know more about TRIANGLE">TRIANGLE</a> <a href="https://interviewquestions.tuteehub.com/tag/pab-589971" style="font-weight:bold;" target="_blank" title="Click to know more about PAB">PAB</a> where PA=AB= <a href="https://interviewquestions.tuteehub.com/tag/5cm-326441" style="font-weight:bold;" target="_blank" title="Click to know more about 5CM">5CM</a> and ∠A=105o<br/><br/>Steps of construction:<br/>(a) Draw a line segment AB=5cm<br/>(b) At point A, draw an angle of 105o<br/> with the help of protractor, i.e., ∠CAB=105o<br/><br/>(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) Taking A as centre, draw an arc with radius 5cm which cuts CA at point P<br/>(d) Join PR<br/>It is the required isosceles triangle PAB</p></body></html> | |