1.

Construct galvanic cells from the following pairs of half cells and calculate their emf at 25^@C Fe^(3+)(0.1M), Fe^(2+) (1M) (Pt) E_(Fe^(3+),Fe^(2+))=0.77volt AgCl(s),Cl^- (0.001M) |Ag E_(AgCl,Cl^-)^@=0.22 volt

Answer»

Solution :For the half cell reaction
`FE^(3+)+e LEFTRIGHTARROW Fe^(2+)`,
`E_(Fe^(3+),Fe^(2+))=E_(Fe^(3+),Fe^(2+))^@-0.0591/1 LOG""([Fe^(2+)])/([Fe^(3+)])`
`=0.77- 0.0591/1 log"" 1/0.1=0.71` volt
And, for the half cell reaction
`AGCL(s)+ e=Ag(s)+CL^(-)`


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