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Convert the equation of plane `2x-4y+3z = 24` into intercept from and find the intercepts cuts from the axes. |
Answer» Equation of plane `2x-4y+3z = 24` `rArr (2x)/(24)-(4y)/(24) + (3z)/(24) = 1` `rArr (x)/(12) + (y)/(-6) + (z)/(8) = 1`. Which is the intercept from of plane. Intercepts on axes are `a = 12, b = - 6, c = 8` |
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