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Copper crystallizes into a fcc lattice with edge length 3.61 xx 10^(-8) cm. Calculate the density of the crystal (Atomic mass of copper = 63.5 g/mol and Avogadro number = 6.022 xx 10^(23) mol^(-1)) |
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Answer» Solution :`d = (ZM)/(a^(3) N_(A))` `d = (4 XX 63.5)/((3.61)^(3) xx 10^(-24) xx 6.022 xx 10^(23))` `d = (254)/(28.33)` d = 8.9 `g//cm^(3)` |
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