1.

Copper sulphate dissolves in excess of KCN to give

Answer»

`[Cu(CN)_(4)]^(2-)`
`Cu(CN)_(2)`
`CuCN`
`[Cu(CN)_(4)]^(3-)`

Solution :KCN first reduces CUPRIC IONS to cuprous ions which are precipitated as cuprous cyanide. This REACTS with excess of `CN^(-)` to form SOLUBLE four-coordinated complex `[Cu(CN)_(4)]^(3-)` which is tetrahedral in shape.
`2Cu^(2+)+4CN^(-)rarr2Cu^(+)CN^(-)+underset("Cyanogen")((CN)_(2))`
`CuCN+3CN^(-)rarr[Cu(CN)_(4)]^(3-)`
or `3KCN+CuCNrarrK_(3)[Cu(CN)_(4)]`


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