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Corner angle of a corner reflector with 4 current elements is ______(a) \(\frac{π}{4}\)(b) \(\frac{π}{2}\)(c) \(\frac{π}{8}\)(d) 4πThe question was posed to me in an online quiz.This intriguing question comes from Corner Reflector topic in chapter Reflector Antenna of Antennas

Answer» RIGHT OPTION is (a) \(\frac{π}{4}\)

For explanation: Corner angle of a corner REFLECTOR with 4 current ELEMENTS is given by \(α=\frac{π}{N}\)

Given N=4

⇨ \(α=\frac{π}{N}=\frac{π}{4}.\)


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