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Corollaries of inscribed angle theorem `:` Angle inscribed in the same arc arc contruent Given `:` (1) A circle with centre O (2) `/_ABD` and `/_ACD ` are inscribed in arc ABC and intercepts arc APD. To prove `:` `/_ABD ~= /_ACD ` |
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Answer» Proof `:` `/_ABD = (1)/(2)` m (arc APD ) ...(1) `/_ACD = (1)/(2) ` m (arc APD ) Inscribed angle theorem ) …(2) From (1) and (2), we get `/_ABD ~= /_ACD ` |
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