1.

Correct method to prepare Me_(3)C-O-Me in good yield is /are :

Answer»

`Me_(3)C-Cl+MeONararr`
`Me_(2)C=CH_(2)underset((II)SBH)overset((ii)HG(O Ac)_(2)+MeOH)rarr`
`Me_(3)C-O Na+MeClrarr`
`Me_(2)C=CH_(2)underset(MeOH)overset(H^(o+))rarr`

SOLUTION :


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