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Correct order of 1st ionisationpotential (IP) among following elements Be, B, C, N, O isA. `B lt Be lt C lt O lt N`B. `B lt Be lt C lt N lt O`C. `Be lt B lt C lt N lt O`D. `Be lt B lt C lt O ltN ` |
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Answer» Correct Answer - A An atom has electronic configuration `1s^(2),2s^(2),2p^(6),3s^(2)3p^(6)3d^(3),4s^(2)` It is a member of d- block element because the last electron is filled in d -subshell as `3d^(3)` and the following electronic configuration is possible for d-subshell as `(n-d)^(( 1 "to"10))` `{:(,"Group number",IIIB,IVB,VB,VIB,VIIB),(,,3,4,5,6,7),(,ns^(2)(n-1)s^(2)p^(6),d^(1),d^(2),d^(3),d^(4),d^(5)):}` `{:(,VIII,VIII,VIII,IB,IIB),(,8,9,10,11,12),(,d^(6),d^(7),d^(8),d^(9),d^(10)):}` Hence, it is member of third group |
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