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Which one of the elements with the following outer orbital configuration may exhibit the larger number of oxidation states ?A. `3d^(3), 4s^(2)`B. `3d^(5), 4s^(1)`C. `3d^(5), 4s^(2)`D. `3d^(2), 4s^(2)` |
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Answer» Correct Answer - C The sum of number of electrons (unpaired) in d-orbitals and number of electrons ins-orbital gives the number of oxidation states (os) exhibited by a d-block element. Therefore. (a) ` 3d^(3),4s^(2) rArr OS = 3+2=5` (b) `3d^(5),4s^(1)rArr OS = 5+1 = 6` (c) `3d^(5), 4s^(2) rArr OS = 5+ 2=7` (d) `3d^(2), 4s^(2) rArr OS = 2+2=4` Hence, element with `3d^(5), 4s^(2)` configuration exhibits largest number of oxidation states. |
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