Saved Bookmarks
| 1. |
Correct statement(s) regarding the graph I) Above 983K, Carbon can reduce any metal oxide at high temperature and itself oxidised to CO (II) In the first reaction (Formation of CO_(2) from 'C') DeltaS^(0)=0& DeltaG^(0) ramains nearly same, i.e. it is independent of temperature III)In the second reaction, (formation of CO), there is increase is entropy & DeltaS^(0)=+ve &DeltaG^(0) becomes more -ve with increase in temperature (IV)In third reaction(formation of CO_(2) from CO) there is a decrease in entropy DeltaS^(0)= -ve& DeltaG^(0) becomes less -ve with increase in temperature |
|
Answer» ONLYI |
|