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(cos(20^circ)^2 %2B cos(70^circ)^2)/(sin(31^circ)^2 %2B sin(59^circ)^2) |
Answer» correct answer is 1 please like and accept as best answer answer is 1 because we take sin values in cos cos^2(20)+ cos^2(70)/ sin^2(59)+ sin^(31)= cos^2(90-20)+ cos^2(70)/ sin^3(59)+ sin^2(90-31)= sin^2(70)+ cos^2(70)/sin^2(59)+ sin^2(90-31)= sin^2(70)+ cos^2(70) / sin^2(59)+ cos^2(59)= 1/1=1 |
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