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cos 40°+ cos 80°+ cos 160°+ cos 240 °= A. 0 B. 1 C. 1/2 D. -1/2 |
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Answer» Option : (D) cos 40° + cos 80° + cos 160° + cos 240° = (cos 40° + cos 80°) + (cos 160° + cos 240°) = 2cos \(\frac{80°+40°}{2}\) cos \(\frac{80°-40°}{2}\)+ 2cos \(\frac{240°+160°}{2}\) cos\(\frac{240°-160°}{2}\) = 2cos 60° cos 20° + 2cos 200° cos 40° = 2⋅ 1/2 ⋅cos 20° + 2cos (180 + 20)° cos 40° = cos 20° - 2cos 20° cos 40° = cos 20° - (cos (40° + 20°) + cos (40° - 20°)) = cos 20° - (cos 60° + cos 20°) = - cos 60° = - 1/2 (Ans) |
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