1.

`(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x`

Answer» LHS.
`=(cos(pi+x).cos(-x))/(sin(pi-x).cos(pi/2+x)) = (-cos x.cos x)/(sinx.(-sinx))`
`=(-cos^(2)x)/(-sin^(2)x)=cot^(2)x`= RHS Hence Proved.


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