Cos²a+ tan^2 - 1 / sin^2 = tan ²Afastttt

1.	Cos²a+ tan^2 - 1 / sin^2 = tan ²Afastttt
Answer» Answer: We KNOW that cos2x+sin2x=1 (Identity) Divide LHS of the GIVEN EXPRESSION by the above identity We have (cos2x−sin2x)/(cos2x+sin2x) ——— 1 Now divide expression 1 above by cos2x and you have the expression on the RHS = (1−tan2x)/(1+tan2x Step-by-step explanation: please MARK me as brainlist

Answer»

Answer:

We KNOW that cos2x+sin2x=1 (Identity)

Divide LHS of the GIVEN EXPRESSION by the above identity

We have (cos2x−sin2x)/(cos2x+sin2x) ——— 1

Now divide expression 1 above by cos2x and you have the expression on the RHS = (1−tan2x)/(1+tan2x

Step-by-step explanation:

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