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CoSO_(4)Cl.5NH_(3) exists in two isomeric forms 'A' and 'B'. Isomer 'A' reacts with AgNO_(3) to give white precipitate, but does not react with BaCl_(2). Isomer 'B' gives white precipitate with BaCl_(2) but does not react with AgNO_(3). Answer the following questions. Identify 'A' and 'B' and write their structural formulas. (ii) Name the type of isomerism involved. (iii) Give the IUPAC name of 'A' and 'B'. |
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Answer» Solution :(i) As ISOMER A reacts with `AgNO_(3)` to give a white PRECIPITATE, Cl must be present in the ionization SPHERE. As it does not react with `BaCl_(2)`, `SO_(4)^(2-)` must be present in coordination sphere. `therefore` Formula of `A=[Co(NH_(3))_(5)SO_(4)]Cl` (coordination no. of Co=6) As reactions are reverse for isomer B, formula `B=[Co(NH_(3))_(5)Cl]SO_(4)` (ii) Ionisation isomerism (iii) A = Pentaamminesulphatocobalt (III) chloride , B = Pentaamminechloridocobalt (III) SULPHATE. |
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