1.

Cost Of An Item Is X. It's Value Increases By P% And Decreases By P% Now The New Value Is 1 Rupee, What Is The Actual Value ?

Answer»

Given cost of an item = RS. X

Item cost by increasing p% will be = x(100+p)/100

After p% decrement, VALUE = {x+(xp/100)}-[{x+(xp/100)}p/100] 

= [x+(xp/100)] [1-(p/100)]

= x[1+(p/100)][1-(p/100)]

GIVNE new value is 1

x[1-((p^2)/10000)] = 1

x = 1/[1-((p^2)/10000)] = 10000/[10000-(p^2)].

Given cost of an item = Rs. X

Item cost by increasing p% will be = x(100+p)/100

After p% decrement, value = {x+(xp/100)}-[{x+(xp/100)}p/100] 

= [x+(xp/100)] [1-(p/100)]

= x[1+(p/100)][1-(p/100)]

Givne new value is 1

x[1-((p^2)/10000)] = 1

x = 1/[1-((p^2)/10000)] = 10000/[10000-(p^2)].


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