`cosx+sinx=1` – InterviewSolution

InterviewSolution

1.	`cosx+sinx=1`
Answer» Correct Answer - `x=(2npi+(pi)/(2))orx=2npi , "where "ninI` `cosx+sinx=1rArr(1)/(sqrt(2))cosx+(1)/(sqrt(2))sinx=(1)/(sqrt(2))` `rArrcosx " cos"(pi)/(4)+sinx " sin"(pi)/(4)=(1)/(sqrt(2))` `rArrcos(x-(pi)/(4))="cos "(pi)/(4)` `rArrx-(pi)/(4)=2npi+(pi)/(4)orx-(pi)/(4)=2npi-(pi)/(4)` `rArrx=2npi+(pi)/(2)orx=2npi " where " n inI`.

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