InterviewSolution
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InterviewSolution
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`cot^(2)pi/6+"cosec"(5pi)/(6) + 3tan^(2)pi/6=6` |
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Answer» LHS `=cot^(2)pi/6 + "cosec"(5pi)/(6)+3tan^(2)pi/6` `=cot^(2)pi/6+"cosec"(pi/6)+3(tanpi/6)^(2)` `=(cot30^(@))^(2) + ("cosec"30^(@))+3(tan 30^(@))^(2)` `=(sqrt(3))^(2)+2+3(1/sqrt(3))^(2)=3+2+1=6` RHS Hence Proved. |
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