1.

`cot17^(@)(cot73^(@)cos^(2)22^(@)+(1)/(Cot17^(@)Sec^(2)68^(@)))` का मान क्या है ?

Answer» Correct Answer - b
`rArrcot17^(@)(cot73^(@)cos^(2)22^(@))+(1)/(cot17^(@)sec68^(@))`
`=cot17^(@)[ cot(90-17^(@))cos^(2)(90-60)+(tan17^(@)cos^(2)68)`
`=cot17^(@)(tan17^(@)cos^(2)68)`
`=cot17^(@)(sin^(2)68+cos^(2)68)`
=1(1)=1


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