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`cot17^(@)(cot73^(@)cos^(2)22^(@)+(1)/(Cot17^(@)Sec^(2)68^(@)))` का मान क्या है ? |
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Answer» Correct Answer - b `rArrcot17^(@)(cot73^(@)cos^(2)22^(@))+(1)/(cot17^(@)sec68^(@))` `=cot17^(@)[ cot(90-17^(@))cos^(2)(90-60)+(tan17^(@)cos^(2)68)` `=cot17^(@)(tan17^(@)cos^(2)68)` `=cot17^(@)(sin^(2)68+cos^(2)68)` =1(1)=1 |
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