`cotx+tanx=2"cosec "x` – InterviewSolution

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1.	`cotx+tanx=2"cosec "x`
Answer» Correct Answer - `x=2npi+-(pi)/(3), "where " n in I` The given equation is `(cosx)/(sinx)+(sinx)/(cosx)=(2)/(sinx)rArrcos^(2)x+sin^(2)x=2cosx` `rArrcosx=(1)/(2)="cos "(pi)/(3)` `rArrx=2npi+-(pi)/(3), "where "n inI`.

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