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Coulomb’s law can be derived from Gauss law. State True/ False(a) True(b) FalseThis question was addressed to me in examination.My question comes from Surface Integral in section Vector Calculus of Electromagnetic Theory

Answer»

Correct answer is (a) True

To elaborate: GAUSS law, Q = ∫∫D.ds

By considering area of a SPHERE, ds = r^2sin θ dθ dφ.

On integrating, we GET Q = 4πr^2D and D = εE, where E = F/Q.

Thus, we get Coulomb’s law F = Q1 x Q2/4∏εR^2.



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