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| 1. |
Cr^(2+) is a strong reducing agent whereas Mn^(3+) with the same d^4 configuration is an oxidising agent. |
| Answer» Solution :`CR^(3+) // Cr^(2+)` has a negative REDUCTION potential or positive oxidation potential. Therefore, `Cr^(3+)` is most stable. Hence, `Cr^(2+)` can EASILY change to `Cr^(3+)` by the loss of an electron. THUS, `Cr^(2+)` acts as a strong reducing agent. On the other hand, `Mn^(3+)//Mn^(2+)` has large positive reduction potential. Hence, `Mn^(3+)` can be easily reduced and thus acts as a strong oxidising agent.` | |