1.

Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)toCr^(++ +)+7H_(2)O,E^(@)=1.33V,3xx[2I^(-)toI_(2)+2e^(-)],E^(@)=-0.54V Find out the value of the equilibrium constant and Gibbs free energy change in the reaction given above.

Answer»


SOLUTION :`E_(CELL)^(@)=1.33+(-0.54)V=0.79V,n=6`.


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