1.

Cr_(2)O_(7)^(2-)+I^(-)toI_(2)+Cr^(3+) E_(cell)^(@)=0.79V,E_(Cr_(2)O_(7)^(2-))^(@)=1.33V,E_(I_(2))^(@)=?

Answer»

`0.54V`
`-0.054V`
`+0.18V`
`-0.18V`

Solution :In the given RACTION, `I^(-)` has been oxidized to `I_(2)` and `Cr_(2)O_(7)^(2-)` ions have been REDUCED to `Cr^(3+)`
`thereforeE_(cell)^(@)=E_(Cr_(2)O_(7)^(2-))^(@)-E_(I_(2))^(@)`
i.e., `0.79=1.33-E_(I_(2))^(@)` or `E_(I_(2))^(@)=0.54V`


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