1.

Cr_2O_23 on raction with HCl and the product on reaction with NaOH(aq) give respectively

Answer»

`CrO_2Cl,CrO_4^(-2)`
`CR(OH)_2,CrO_(4)^(2-)`
`Cl_2,Cr_2O_(7)^(-2)`
`Cl_(2).Cr(OH)_3`

Solution :`Cr_2O_7^(-2) + 3Sn^(+2) rarr 3Sn^(+4) + 2Cr^(+3)`


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