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[Cr(NH_(3))_(6)]^(3+) is paramagnetic while [Ni(CN)_(4)]^(2-) is diamagnetic. Explain, why ? |
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Answer» Solution :`[Cr(NH_(3))_(6)]^(3+)` is paramagnetic. The oxidation state of Cr in this complex is +3. Hence, we have ELECTRONIC configuration of `Cr^(3+)` `d^(2)sp^(3)` hybridisation  As NH3 is a weak LIGAND, pairing of electrons does not TAKE place. Hence, `d^(2)sp^(3)` hybridisation takes place forming inner complex with octahedral SHAPE. As there are three unpaired electrons, the compound is paramagnetic. `[Ni(CN)_(4)]^(2-)` is diamagnetic due to the absence of unpaired electrons. |
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