1.

Cr2O72- + C2H4O- → C2H4O2 + Cr3+ in acid solution by ion electron method.

Answer»

Cr2O72- + C2H2O- → C2H2O + Cr3+  ...(i)

Here Cr2O72- → 2Cr3+

i.e., Cr2O72- → 2Cr3+ + 7H2O

6e- + 14H+ + Cr2O72- → 2Cr3+ + 7H2O

[H2O + C2H4O- → C2H4O2 + 2H+ + 3e-] x 2    ...(ii)

10H+ + Cr2O72- + 2C2H4O→ 2C2H4O2 + 2Cr3+ + 5H2O



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