1.

Critical angle for a medium is sin^(-1) (0.6), then polarization angle for this medium is ......

Answer»

<P>`sin^(-1)(0.8)`
`sin^(-1)(1.5)`
`TAN^(-1)(1.6666)`
`tan^(-1)(0.6)`

Solution :Critical ANGLE `C= sin^(-1)(0.6)`
`:. sinC=0.6`
`:.(1)/(n)=0.6`
`:.n=(1)/(0.6)`
`:. "tan" theta_(p)=(1)/(0.6) "" [ :. n= tan theta_(p)]`
`:. theta_(p)=tan^(-1)((1)/(0.6))`
`:.theta_(p)tan^(-1)((1.6666)`


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