1.

CrO_(4)^(2-)(yellow) changes to Cr_(2)O_(7)^(2-)(orange) in pH=x and vice-versa in pH=y. Hence, x and y are:

Answer»

`6, 8`
`6, 5`
`8, 6`
`7, 7`

Solution :`2CrO_(4)^(2-)+2H^(+) to Cr_(2)O_(7)^(2-)+H_(2)O`
`Cr_(2)O_(7)^(2-)+2OH^(-) to 2CrO_(4)^(2-)+H_(2)O`


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