1.

CrO_(4)^(2-) (yellow) changes to Cr_(2)O_(7)^(2-)(orange ) in pH=y . Hence x and y are :

Answer»

`6,8`
`6,5`
`8,6`
`7,7`

Solution :`2CrO_(4)^(2-)+2H^(+)rarrCr_(2)O_(7)^(2)+H_(2)O`
`Cr_(2)O_(7)^(2-)+2OHrarr2CrO_(4)^(2-)+H_(2)O`


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