InterviewSolution
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InterviewSolution
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CsBr crystallizes in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 × `10^(23)` mol–1, the density of CsBr is:-A. `42.5 g/cm^(3)`B. ` 0.425 g/cm^(3) `C. `8.25 g/cm^(3)`D. ` 4.25 g/cm^(3) ` |
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Answer» Correct Answer - D For CsBr no. of formulas/unit cell n=1(like CsCI type) `C.D=(nxxM)/(VxxN_(A))``[{:(M=133+80=213),(V=a^(3)=(436.6xx10^(-12))^(3)):}]` `C.D=(1xx213gm)/(83.22xx10^(-12)cm^(3)xx6.02xx10^(23))=4.25gm//cm^(3)` |
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