1.

CsCl crystalises in body centred cubic lattice. If 'a' is its edge length then which of the following expression is correct ?

Answer»

`r_(Cs^(+))+r_(Cl^(-)) = 3a`
`r_(Cs^(+))+r_(Cl^(-)) = (3a)/(2)`
`r_(Cs^(+))+r_(Cl^(-)) = (sqrt(3))/(2)a`
`r_(Cs^(+))+r_(Cl^(-)) = sqrt(3)a`

Solution :EDGE LENGTH =a
Face diagonal = `sqrt( 2) a `
Body diagonal `= sqrt( 3) a `
Since `Cl^(-)` ions are PRESENT at the corners of the CUBE and `Cs^(+)`ion is at the body centre.
`2 ( R _(Cs^(+)) + r_(Cl^(-))) = sqrt( 3). a `
`:. r_(Cs^(+)) + r_(Cl^(-))= ( sqrt( 3) a)/( 2)`


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