1.

Cu^(2+) + 2e rarr Cu(s). For the graph between log[Cu^(2+)] versus E_("red") a straight line of intercept 0.34 V is obtained. Then electrode potential of the half-cell Cu// Cu^(2+)(0.1 M) will be :

Answer»

`[0.34+(0.0591)/2]V`
`[-0.34-(0.0591)/2]V`
`0.34 V`
`[-0.34+(0.0591)/2]V`

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