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Cu^(+), Zn^(2+) are diamagnetic. Prove it. |
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Answer» Solution :`Cu^(+), Zn^(2+)` electronic configuration `[AR] 3d^(10)` The number of unpaired electron is 0. `MU= sqrt( 0(0+2)) = 0 mu_(B)`. So `Cu^(+), Zn^(2+)` are DIAMAGNETIC. |
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