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Cu^(+), Zn^(2+), Sc^(3+), Ti^(4+) are colourless. Prove this statement. |
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Answer» Solution :`(i) Cu^(+)`, `ZN^(2+)` have `d^(10)` CONFIGURATION and `SC^(3+)`, `Ti^(4+)` have `d^(1)` configuration . `(ii)d-d` transition is not possible in the above COMPLEXES. So they are colourless. |
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