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Cube root of √4 + \(\sqrt{36}\) is A) \(\sqrt[3]{144}\)B) 8 C) 2 D) \(\sqrt[3]{40}\) |
Answer» Correct option is (C) 2 \(\sqrt{4}+\sqrt{36}\) = 2+6 = 8 Cube root of \(\sqrt{4}+\sqrt{36}\) is \((\sqrt{4}+\sqrt{36})^\frac13\) \(=(8)^\frac13=(2^3)^\frac13=2\) Correct option is C) 2 |
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