1.

CuCl is sparingly soluble in water but it dissolves in KCl solution due to the formation of

Answer»

`K_(2)[CuCl_(4)]`
`K_(2)[CuCl_(4)]`
`K[CuCl_(2)]`
NONE of the above.

Solution :Hybrid state of NI in `Ni(CO)_(4)` is `sp^(3)` Ni(0) has CONFIGURATION `3d^(8)4s^(2)`. At the time of bonding two electrons of 4s-level go to 3d-orditals the 4s and 4p-orbitals hybridise to assume `sp^(3)` hybrid state.


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